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# FORM TWO CHEMBA BASIC MATHEMATICS MOCK EXAMINATIONS WITH ANSWERS | MTIHANI NA MAJIBU (MARKING SCHEME) YA MTIHANI WA MOCK BASIC MATHEMATICS WILAYA YA CHEMBA

MINISTRY OF EDUCATION AND VOCATION TRAINING

CHEMBA DISTRICT COUNCIL

FORM TWO MOCK ASSESSMENT

041                                                 BASIC MATHEMATICS

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TIME 2:30 HOURS        YEAR: 2020

Instructions

1.    This paper consists of ten (10) compulsory questions.

2.    Show clearly all the working and answers in a space provided.

3.    All writing must be in blue or black ink except drawing must be in pencil.

4.    Mathematical tables, geometric instruments and graph papers may be used where necessary

5.    All communication devices and calculators are not allowed in assessment room.

6.    Write your assessment Number in top write corner of every page.

FOR ASSESSOR’S USE ONLY

 QUESTION NUMBER SCORE ASSESSOR’S  INITIALS 1 2 3 4 5 6 7 8 9 10 TOTAL CHECKER'

1      (a)  Find the sum of all prime numbers between 80 and 100

(b)  Round off:

(i) 9.67 to ones,

(ii) 0.205 to one decimal place,

(iii) 0.197 to two decimal places,

Hence, estimate the value of

2.          (a)  Evaluate   0.4 + 25%  (0.22 0.2) +  0.45)

(b)  If the new price of selling shoe is 40000Tsh. Find the percentage increase of price if the old price was 30000Tsh.

3.          (a)  If the bus starts the journey from Babati at  0600 and takes eight hours and a half to reach at Chemba bus  terminal. Write the time taken to reach in 24 hours clock.

(b) If 50000Tsh of money was invested at a bank which provide the rate of 5%. Find the amount at a bank after 4 years.

4        (a) Find the value of  an angle marked in letter f,g and k in the figure below.

b) Find the perimeter of square ,if its area is 36cm2

5 (a)   The sum of two numbers is 127. If  thedifference between the number is 7, Find the numbers

(b)  Solve the equation   by using quadratic formula.

6   a) If the line passes through the point (3,4) and (2,6). Find

i)                 The slope of the line.

ii)              The equation of line in form of Y = MX+C

b)  The vertices of the triangle are A(2,2) , B (3,4) and C (4,3). If the triangle is reflected under x-axis ,Write down the coordinate of the image of points A, B and C

7.     (a)Find the value of p given that  ( )2p +1 = ( )3p.

(b)   (i) Find the value of 0.0000125  in standard notation.

(ii) Simplify the expression (3 +  ) (4  )

8 (a) solve for the x in the inequality

3X – 4>, X+16

(b) Factorize the expression a2-b2

Hence find the exact valueof 6722-3282

9 the right angled triangle in the figure below has sides of length 7 , 24  cm and 150cm

S

(a)Calculate the value of .

(b)Calculate the area of the triangle

10   (a) There are 48 men at the meeting of whom 24 are teachers, 36 are parents and 16 are both teachers and parents . By using venndiagram , find the number of men who are neither teacher nor parents.

b)  The marks of 100 student were recorded as follow,

 Marks 41 - 50 51 -60 61 - 70 71 - 80 81 -90 91 - 100 Number of students 10 22 34 25 7 2

i)                Which mark were scored by many student  ………………………………….

ii)              Which marks was the lowest mark ………………………………………………….

iii)            If 50% was the pass mark of the test if above 50%, How many student passed examination

MINISTRY OF EDUCATION AND VOCATION TRAINING

CHEMBA DISTRICT COUNCIL

FORM TWO MOCK ASSESSMENT

041                                                    BASIC MATHEMATICS

MARKING SCHEME

01. a)    prime numbers between 80 and 100

83,,89,91,and 97

Sum: 83 +89+91+97 =360 (5 marks)

b) i) 10   (1 mark)

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ii) 0.2(1 mark)

iii) 0.2(1 mark)

=

= 10(1 mark)

02  a) 0.4 + (25%  (0.22 0.45)

o.4 +(­  1.1) + 1/4 0.45)

0.4 + (0.25 + 0.25  0.45)              (05 marks)

0.90 – 1.1-0.45

-0.65

b) new price (NP) = 40000

0ld price (OP) = 30000

Difference cost (DP) = NP-OP

= 40000

DP  = 10000

Percentage cost increase  =  100%

=  100%

=  100%

Percentage cost increase = 33.33%             (05 marks)

03  a) The bus Started Babati 0600

Time taken =8 :30 hours   (02 marks)

Time taken to reaches Msamvu  = 1430hrs   (02 marks)

b)  Principal (P)   =  50000/=

Rate (R) =5%

Time taken (T) = 4years

Amount corrected  (A)= ?

From;    I  =        (01mark)

=       (01mark)

Interest (I)  = 10000/=

Amount (A) = Principal + Interest

= 50000/= + 10000/=      (01mark)

= 60000/=

Amount corrected after 4 years =60000/=      (01mark)

04.

56 + 50 + g =180

106 +g =180

g =180106

g= 74

30 + g + h = 180

But; g = 74

30 + 74  + h = 180

104 + h = 180

h = 180 104

h = 76

f + k +30 = 180

but  f =h

f = 76

76 + k +30 = 180                    (06 marks)

K + 106 = 180

K  = 180 106

K  = 74

 f k g 76 74 74

b)  Area of square = 36cm2

Area = LL      (01mark)

36cm2 = L2

6cm  = L      (01mark)

Length of square = 6cm

Perimeter  = 2(L + W)

=2 (6cm +6cm)      (01mark)

= 212cm

Perimeter of square = 24 cm      (01mark)

5a)  Let ; first number be x

Second number be y

…………(i)

……………….(ii)

By elimination method

+

2 =127 + 7

2 =134

= 67

Y  =127

2y = 120

Y = 60

X,y  = 67 ,60

b)  4

a = 4  , b = -32 and c =12

x =

6  (a)  points (3,4) and (2,6)

(i)   Slope =

Slope =

Slope =

Slope = -1

(ii)  Equation

Slope    =

But slope =-1

-1 =

-1(2   =  6

-2 + x  =  6

Y = x + 6 + 2

Y =x + 8

b) Reflection under x- axis

 point 2,2 3,4 4,3 reflection 2,-2 3,-4 4,-3

7 (a)  )2p + 1 =( )3p

)2p + 1 = ( )6p

)2p + 1 = ( )-6p

2p + 1   =-6p

2p + 6p = -1

8p = -1

P =

( b)  0.0000125  8000 =(1.25  105) 8 3)

= 1.25 8 1053

= 10  108

= 1 1 108

= 1 9

ii)       (3 +  )(4 2)   = (3  4  6 + 42)

= (12  222)

= 8 - 2

(3 +  )(4 2)   = 8 – 2

8. (a) Required to show that

Now consider tri

Angle APQ and ABC

Then,                   (corresponding sides)

(Corresponding sides)

(Corresponding sides)

Hence, triangle APQ is similar to triangle ABC by (sss)

(b) Given a rectangular ABCD and WXYZ as shown below,

Then, ratios of the corresponding sides are given as

Hence value of

9. (a)  from Pythagoras theorem

a2   b2  = c2

(7x)2 + (24x)2  = 1502

49x2  + 576x2  = 22500

625x2  = 22500

X2  =

X2 = 36

X    = 6

( b)          given  5 = 3

Consider the triangle

from Pythagoras theorem

a2   b2  = c2

32 + b2  = 52

9  + b2  = 25

b2  = 25 – 9

b2  = 16

b   =  4

=

2 + 3  =  2

10. (a) Consider the figure below,

From the figure above where P is parent, T is teachers and U is union, then

There for, 4 men are neither teacher nor parents

(b)  From the given figure,

(i) Marks scored by many students is at the highest frequency 34

Hence, 61-70 marks are scored by many students.

(ii)Lowest marks is at frequency of 10, hence the lowest marks is 41-50

(iii) If  was pass mark, then students who pass examination is